(2x-5)*(x^2-3x+2)=0

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Solution for (2x-5)*(x^2-3x+2)=0 equation: 


Simplifying
(2x + -5)(x2 + -3x + 2) = 0

Reorder the terms:
(-5 + 2x)(x2 + -3x + 2) = 0

Reorder the terms:
(-5 + 2x)(2 + -3x + x2) = 0

Multiply (-5 + 2x) * (2 + -3x + x2)
(-5(2 + -3x + x2) + 2x * (2 + -3x + x2)) = 0
((2 * -5 + -3x * -5 + x2 * -5) + 2x * (2 + -3x + x2)) = 0
((-10 + 15x + -5x2) + 2x * (2 + -3x + x2)) = 0
(-10 + 15x + -5x2 + (2 * 2x + -3x * 2x + x2 * 2x)) = 0
(-10 + 15x + -5x2 + (4x + -6x2 + 2x3)) = 0

Reorder the terms:
(-10 + 15x + 4x + -5x2 + -6x2 + 2x3) = 0

Combine like terms: 15x + 4x = 19x
(-10 + 19x + -5x2 + -6x2 + 2x3) = 0

Combine like terms: -5x2 + -6x2 = -11x2
(-10 + 19x + -11x2 + 2x3) = 0

Solving
-10 + 19x + -11x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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